0.005x^2-24x+8800=0

Solution for 0.005x^2-24x+8800=0 equation:

0.005x^2-24x+8800=0

a = 0.005; b = -24; c = +8800;
Δ = b2-4ac
Δ = -242-4·0.005·8800
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-20}{2*0.005}=\frac{4}{0.01}
=400
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+20}{2*0.005}=\frac{44}{0.01}
=4400
$